Talk:Rose (mathematics)

Lissajous

This seems to be quite comparable to Lissajous curves. --Abdull 18:53, 27 May 2006 (UTC)[reply]

If the point is that a lissajous curve can specify a rose, please find the parameters for the eqivalence. 2601:140:8980:4B20:528:3DF3:2917:4EDF (talk) 01:05, 20 February 2021 (UTC)[reply]

Merge from/new Rhodonea article

I agree. I would have suggested/done the same myself if only I could have remembered the name of the Rose (mathematics) article. —David Eppstein 05:51, 22 February 2007 (UTC)[reply]

Definitely agree. No reason to have two articles, especially as they are both so minimal. Doctormatt 16:45, 22 February 2007 (UTC)[reply]

Agree with proposed merge. Gandalf61 17:33, 22 February 2007 (UTC)[reply]

Pictures

I just noticed that while the article gives the rose in terms of cosine, the pictures are all for sine. Do we

change the article to make sine the basic one (and relate cosine to it as a rotation)?
change the pictures? (Sounds like a pain.)
change the captions on the pictures to be more specific?

VectorPosse 17:09, 4 April 2007 (UTC)[reply]

Ack. I'll change the images (the second one is okay). It'll be done in a few hours, probably. Cheers, Doctormatt 20:04, 4 April 2007 (UTC)[reply]

I updated the seven petal image and added info to the "rose gallery" image to make it clear these are r=sin k \theta. I think this works. Cheers, Doctormatt 04:36, 5 April 2007 (UTC)[reply]

Area

The right side of the Area formula suggests that the Area is independent of k! —Preceding unsigned comment added by 91.36.95.125 (talk) 02:54, 30 December 2007 (UTC)[reply]

The area of each petal is dependent on k. See the article. 2601:140:8980:4B20:528:3DF3:2917:4EDF (talk) 23:58, 19 February 2021 (UTC)[reply]

For irrational k the curve won't fill the unit disc

In that case the curve will be dense in the unit disc, but it won't "fill" it completely. To see this, just imagine a circle around the origin or a straight line that crosses the unit disc. The rose will cross or touch this line/circle just countably inifinite times, but there are more than countably infinite points the rose would have to hit in order to fill the entire disc. --Georg-Johann (talk) 18:00, 4 September 2010 (UTC)[reply]

"offset parameter"

Here are some images generated from the generalized rose-limaçon equation r=b+sin(aθ): ... AnonMoos (talk) 21:44, 23 July 2014 (UTC)[reply]

3d Rose Curves

What are these things called? https://www.youtube.com/watch?v=Y7utC53CNs4

Do they have a name? Do they deserve a name? Am I over stepping any boundaries calling them 3d Rose Curves? -- 18:14, 28 March 2015‎ Tejolson

2018

I am unable to reproduce the current Rose-rhodonea-curve-7x9-chart-improved.svg using r=cos(k \theta). Here is what I got instead:

Is there anything I am missing, or the figure in question is not properly computed? — Preceding unsigned comment added by HamdiSahloul (talk • contribs) 16:32, 3 December 2018 (UTC)[reply]

Something is very wrong. Check against curves generated using desmos on desmos.com. The chart asvof this date compares favorably. (Read the caption.) 2601:140:8980:4B20:528:3DF3:2917:4EDF (talk) 00:09, 20 February 2021 (UTC)[reply]

Limaçon article

Roses are sinusoids with no offset parameter. Those things are limacons. There is an article on them: limaçon. 2601:140:8980:4B20:DAA:DAE7:8979:2DE5 (talk) 01:56, 5 February 2021 (UTC)[reply]

Missing video

The video is no longer available. 2601:140:8980:4B20:528:3DF3:2917:4EDF (talk) 01:02, 20 February 2021 (UTC)[reply]

Roses specified by other curves

This article needs a section on other curve types that specify roses like the hypotrochoid. Such a section which enrich understanding of both types greatly! 2601:140:8980:4B20:528:3DF3:2917:4EDF (talk) 01:49, 20 February 2021 (UTC)[reply]